Q73 / 90 · JEE Main 2012 (19 May Online) · Physics
Ionisation energy of Li (Lithium) atom in ground state is $5.4 \mathrm{eV}$. Binding energy of an electron in $\mathrm{Li}^{+}$ion in ground state is $75.6 \mathrm{eV}$. Energy required to remove all three electrons of Lithium (Li) atom is
- A$81.0 \mathrm{eV}$
- B$135.4 \mathrm{eV}$
- C$203.4 \mathrm{eV}$
- Correct answerD$156.6 \mathrm{eV}$
Hence, the correct answer is option: 'D'.