Interference fringes are obtained in a Young double slit experiment using beam of light consisting two wavelengths $500 \mathrm{nm}$ and $600 \mathrm{nm}$. Bright fringes due to both wavelengths coincide at $2.5 \mathrm{mm}$ from the central maximum. If the separation between the slits is $3 \mathrm{mm}$, then the distance between the screen and plane of the slits is

• A

  $1.2 \mathrm{m}$
• B

  $2.8 \mathrm{m}$
• Correct answer
  C

  $2.5 \mathrm{m}$
• D

  $3.2 \mathrm{m}$

Hence, the correct answer is option: 'C'.