Q30 / 155 · WBJEE 2026 · Chemistry

Indicate the major product of the following reaction:
Figure

  • A
    Figure
  • B
    Figure
  • Correct answer
    C
    Figure
  • D
    Figure

Solution

The reaction of a secondary alkyl halide with a strong base ($\text{CH}_3\text{ONa}$) proceeds via an E2 elimination mechanism.

E2 elimination in a cyclohexane ring requires an anti-periplanar (trans-diaxial) arrangement of the leaving group and the $\beta$-atom being abstracted.

In the reactant, the -Br group is on a wedge (up). For anti-periplanar elimination, the $\beta$-atom must be on a dash (down).

At the upper $\beta$-carbon, the -$\text{CH}_3$ group is on a dash, but it cannot be eliminated. The -H atom is on a wedge, so it is syn-periplanar and cannot be eliminated.

At the lower $\beta$-carbon, the -D atom is on a dash, making it anti-periplanar to the -Br group. The -H atom is on a wedge.

Therefore, the base abstracts the anti-periplanar -D atom, leading to the elimination of DBr and the formation of a double bond at the lower position.

The resulting product retains the -H atom on the newly formed vinylic carbon and the original stereochemistry at the upper allylic carbon, which corresponds to option (C).

Answer: Figure

Hence, the correct answer is option: 'C'.

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