Q97 / 160 · JIPMER 2011 · Physics

In Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

  • A
    $\sin ^{-1}(0.01)$
  • B
    $\sin ^{-1}(0.0001)$
  • Correct answer
    C
    $\sin ^{-1}(0.001)$
  • D
    $\sin ^{-1}(0.1)$

Solution

In Young's double slit experiment, half angular width is given by $\sin \theta=\frac{\lambda}{d}$ $=\frac{589 \times 10^{-9}}{0.589 \times 10^{-3}}=10^{-3}$ $\theta=\sin ^{-1}(0.001)$

Hence, the correct answer is option: 'C'.

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