Q16 / 107 · NTA Abhyas (JEE Main) 2020 · Physics · Wave Optics

In Young’s double-slit experiment, the distance between the two identical slits is 6.1 times larger than the slit width. Then the number of intensity maxima observed within the central maximum of the single-slit diffraction pattern is :

  • A
    3
  • B
    6
  • C
    24
  • Correct answer
    D
    12

Solution

d = separation between 2 slits

a = slit width

β y = fringe width in YDSE &  β D = width of central maxima

βy=λDd=λD6.1a;βD=2λDa

β D =2×6.1  β y

=12.2  β y

Hence, the correct answer is option: 'D'.

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