Q65 / 90 · JEE Main 2016 (09 Apr Online) · Physics

In Young's double-slit experiment, the distance between slits and the screen is 1 m and monochromatic light of wavelength 600 nm is being used. A person standing near the slits is looking at the fringe pattern. When the separation between the slits is varied, the interference pattern disappears for a particular distance d0 between the slits. If the angular resolution of the eye is 160°, then the value of d0 is close to

  • A
    1 mm
  • B
    3 mm
  • Correct answer
    C
    2 mm
  • D
    4 mm

Solution

When the angular fringe width in the interference pattern becomes less than the angular resolving power of the person's eye, the fringes will disappear.

The angular fringe width θ 0 = β D = λ d 0

d 0 = λ θ 0 = 600× 10 −9 ( 1 60 × π 180 )

d0=600×60×180×10−9π m=2 mm

Hence, the correct answer is option: 'C'.

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