Q9 / 160 · AP EAMCET 2019 (20 Apr Shift 1) · Chemistry

In which of the following, the solubility of \(\mathrm{AgCl}\) will be minimum?

  • A
    \(0.1 \mathrm{M} \mathrm{KNO}_3\)
  • Correct answer
    B
    \(0.1 \mathrm{M} \mathrm{KCl}\)
  • C
    \(0.2 \mathrm{M} \mathrm{KNO}_3\)
  • D
    Water

Solution

Solubility of \(\mathrm{AgCl}\) in \(0.1 \mathrm{M} \mathrm{KCl}\) will be less because of common ion effect of \(\mathrm{Cl}^{-}\) \(\begin{aligned} & \mathrm{AgCl} \rightleftharpoons \mathrm{Ag}^{+}+\mathrm{Cl}^{-\prime} \quad \text{(Common ion)} \\ & \mathrm{KCl} \rightleftharpoons \mathrm{K}^{+}+{ }^{\prime} \mathrm{Cl}^{-}{ }^{\prime} \\ \end{aligned}\) Hence, option (2) is correct.

Hence, the correct answer is option: 'B'.

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