Q3 / 160 · AP EAMCET 2020 (17 Sep Shift 2) · Chemistry

In which of the following molecule/ion, all the bonds are not equal?

A
\(\mathrm{XeF}_4\)
B
\(\mathrm{BF}_4^{-}\)
Correct answer
C
\(\mathrm{C}_2 \mathrm{H}_4\)
D
\(\mathrm{SiF}_4\)

Solution

In \(\mathrm{XeF}_4, \mathrm{BF}_4^{-}\)and \(\mathrm{SiF}_4\) only one type of covalent bonds are present, which are \(\mathrm{Xe}-\mathrm{F}, \mathrm{B}-\mathrm{F}\) and \(\mathrm{Si}-\) F respectively. In \(\mathrm{C}_2 \mathrm{H}_4\), two types of covalent bonds are present, which are \(\mathrm{C}=\mathrm{C}\) and \(\mathrm{C}-\mathrm{H}\). which are not equal for any property.

Hence, the correct answer is option: 'C'.

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