Q47 / 60 · JEE Advanced 2013 (Paper 1) · Physics

In the Young's double slit experiment using a monochromatic light of wavelength λ , the path difference ( in terms of an integer n ) corresponding to any point having half the peak intensity is

  • A
    2 n + 1 λ 2
  • Correct answer
    B
    2 n + 1 λ 4
  • C
    2 n + 1 λ 8
  • D
    2 n + 1 λ 16

Solution

I max = 4 I ​
∴     2 I = 2 I + 2 I cos θ
cos  θ = 0 ⇒ θ = 2 n + 1 π 2
2 π λ x  =  2 n + 1 π 2
x = 2 n + 1 λ 4

Hence, the correct answer is option: 'B'.

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