In the YDSE arrangement shown here, the intensity on the screen due to slit-2 is four times that of slit-1. If resultant intensity at the position of central maxima $O$ is $I$, the resultant intensity at point P, where the phase difference between two waves coming from two slits is ${\text{cos}}^{-1}\left(\frac{1}{4}\right)$ is


      

• A

  $\frac{I}{3}$
• Correct answer
  B

  $\frac{2I}{3}$
• C

  $\frac{I}{4}$
• D

  $\frac{I}{2}$

Hence, the correct answer is option: 'B'.