Q25 / 90 · JEE Main 2021 (26 Aug Shift 2) · Chemistry

In the sulphur estimation, $0.471 g$ of an organic compound gave $1.44 g$ of barium sulfate. The percentage of sulphur in the compound is. (Nearest integer) (Atomic Mass of $Ba = 137 u$ )

Correct answer: 42

Solution

$233 g$ of ${BaSO}_{4}$ contains $32 g$ sulphur.

Amount of $S$ in $1.44 g$ of ${BaSO}_{4} = \frac{32}{233} \times 1.44$

So percentage of $S$ in $0.471$ of organic compound $= \frac{32}{233} \times \frac{1.44}{0.471} \times 100 = 42 %$

Hence, the correct answer is 42.