In the reaction, $\mathrm{M}\mathrm{n}{\mathrm{O}}_{4\mathrm{}\left(\mathrm{a}\mathrm{q}.\right)}^{-1}+\mathrm{B}{\mathrm{r}}_{\left(\mathrm{a}\mathrm{q}.\right)}^{-1}\to \mathrm{M}\mathrm{n}{\mathrm{O}}_{2\left(\mathrm{s}\right)}+\mathrm{B}\mathrm{r}{\mathrm{O}}_{3\mathrm{}\left(\mathrm{a}\mathrm{q}\right)}^{-1},$ the correct change in oxidation number of the species involved is

• A

  $\mathrm{B}{\mathrm{r}}^{+5}$ to $\mathrm{B}{\mathrm{r}}^{-1}$
• B

  $\mathrm{M}{\mathrm{n}}^{+7}$ to $\mathrm{M}{\mathrm{n}}^{+2}$
• C

  $\mathrm{M}{\mathrm{n}}^{+7}$ to $\mathrm{M}{\mathrm{n}}^{+3}$
• Correct answer
  D

  $\mathrm{B}{\mathrm{r}}^{-1}$ to $\mathrm{B}{\mathrm{r}}^{+5}$

Hence, the correct answer is option: 'D'.