Q133 / 160 · AP EAMCET 2020 (17 Sep Shift 1) · Physics

In the nuclear reaction, \({ }_6^{11} \mathrm{C} \rightarrow{ }_5^{11} \mathrm{~B}+\beta+X, X\) stands for

  • A
    a neutron
  • B
    an electron
  • Correct answer
    C
    a neutrino
  • D
    an anti-neutrino

Solution

Nuclear reaction is given as \({ }_6^{11} \mathrm{C} \rightarrow{ }_5^{11} \mathrm{~B}+\beta+X\) ...(i) When positron ( \(\beta\) ) is emitted from a nuclei, then atomic number decreases by one unit, while the mass number remains the same. Hence, Eq. (i) is written as \({ }_6^{11} \mathrm{C} \rightarrow{ }_5^{11} \mathrm{~B}+{ }_1^0 \beta+v \text { (neutrino) }\) Hence, \(X\) is a neutrino v.

Hence, the correct answer is option: 'C'.

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