In the given reactions, ' $\mathrm{X}$ ' and ' $\mathrm{Y}$ ' respectively are $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{NH}_2 \stackrel{\mathrm{X}}{\longleftrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CONH}_2 \stackrel{\mathrm{Y}}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2$

• Correct answer
  A

  $\mathrm{LiAlH}_4, \mathrm{H}_2 \mathrm{O} ; \mathrm{Br}_2 / \mathrm{OH}^{-}$
• B

  $\mathrm{Br}_2 / \mathrm{OH}^{-} ; \mathrm{LiAlH}_4, \mathrm{H}_2 \mathrm{O}$
• C

  $\mathrm{Br}_2 / \mathrm{H}^{+} ; \mathrm{NaBH}_4$
• D

  $\mathrm{NaBH}_4 ; \mathrm{Br}_2 / \mathrm{H}^{+}$

Hence, the correct answer is option: 'A'.