Q55 / 180 · KCET 2025 · Chemistry

In the given graph, $\mathrm{E}_{\mathrm{a}}$ for the reverse reaction will be Figure

  • Correct answer
    A
    125 KJ
  • B
    215 KJ
  • C
    90 KJ
  • D
    305 KJ

Solution

$\begin{aligned} & \Delta H=\left(E_a\right)_f-\left(\mathrm{E}_{\mathrm{a}}\right)_{\mathrm{b}} \\ & 90=215-\left(\mathrm{E}_{\mathrm{a}}\right)_{\mathrm{b}} \\ & \left(\mathrm{E}_{\mathrm{a}}\right)_{\mathrm{b}}=215-90=125 \mathrm{KJ}\end{aligned}$

Hence, the correct answer is option: 'A'.

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