In the given figure, there is a circuit of potentiometer of length AB=10 m. The resistance per unit length is 0.1 Ω per cm. Across AB, a battery of…

Question

In the given figure, there is a circuit of potentiometer of length $A B = 10 m$ . The resistance per unit length is $0.1 Ω$ per $cm$ . Across $A B$ , a battery of emf $E$ and internal resistance $r$ is connected. The maximum value of emf measured by this potentiometer is:

MARKS Content Team · Accepted Answer

Correct answer: (A) 5 V. Maximum voltage that can be measured by this potentiometer will be equal to potential drop across AB, R_AB=10×0.1×100=100 ohm ∴ V_AB=6/(20+100)×100=6×100/120=5 V

In the given figure, there is a circuit of potentiometer of length $A B = 10 m$ . The resistance per unit length is $0.1 Ω$ per $cm$ . Across $A B$ , a battery of emf $E$ and internal resistance $r$ is connected. The maximum value of emf measured by this potentiometer is:

Solution

Relevant Questions

In the given figure, there is a circuit of potentiometer of length AB=10 m. The resistance per unit length is 0.1 Ω per cm. Across AB, a battery of emf E and internal resistance r is connected. The maximum value of emf measured by this potentiometer is:

Solution

Relevant Questions

In the given figure, there is a circuit of potentiometer of length $A B = 10 m$ . The resistance per unit length is $0.1 Ω$ per $cm$ . Across $A B$ , a battery of emf $E$ and internal resistance $r$ is connected. The maximum value of emf measured by this potentiometer is: