Q145 / 160 · AP EAMCET 2024 (18 May Shift 1) · Physics

In the given circuit, the potential difference across $5 \mu \mathrm{~F}$ capacitor is Figure

  • Correct answer
    A
    48 V
  • B
    24 V
  • C
    63 V
  • D
    21 V

Solution

$\begin{gathered}C_1=5 \mu \mathrm{~F}, \mathrm{C}_2=(4+8+4)=16 \mu \mathrm{~F} \\ \therefore \mathrm{~V}_1=\left(\frac{\mathrm{C}_2}{\mathrm{C}_1+\mathrm{C}_2}\right) \mathrm{V}=\left(\frac{16}{16+5}\right) 63=48 \mathrm{~V}\end{gathered}$

Hence, the correct answer is option: 'A'.

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