Q76 / 90 · JEE Main 2024 (29 Jan Shift 2) · Physics

In the given circuit, the current in resistance $R_{3}$ is:

Correct answer
A
$1 A$
B
$1.5 A$
C
$2 A$
D
$2.5 A$

Solution

Equivalent resistance, $R_{eq} = 2 Ω + \frac{4 \times 4}{4 + 4} Ω + 1 Ω = 5 Ω$

Current through battery, $i = \frac{V}{R_{e q}} = \frac{10}{5} = 2 A$

Current in resistance $R_{3} = 2 \times (\frac{4}{4 + 4})$

$= 2 \times \frac{4}{8}$

$= 1 A$

Hence, the correct answer is option: 'A'.

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