Q66 / 90 · JEE Main 2024 (31 Jan Shift 1) · Physics

In the given arrangement of a doubly inclined plane two blocks of masses M and m are placed. The blocks are connected by a light string passing over an ideal pulley as shown. The coefficient of friction between the surface of the plane and the blocks is 0.25. The value of m, for which M=10 kg will move down with an acceleration of 2 m s-2, is: (take g=10 m s-2 and tan 37°=34)

Figure

  • A
    9 kg
  • Correct answer
    B
    4.5 kg
  • C
    6.5 kg
  • D
    2.25 kg

Solution

Figure

For M block:

10gsin53°-μ(10g) cos53°-T=10×2

⇒T=80-15-20

⇒T=45 N

For m block:

T–mg sin 37°-μ mg cos 37°=m×2

⇒45=10 m

⇒m=4.5 kg

Hence, the correct answer is option: 'B'.

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