In the Freundlich isotherm $\left(\frac{\chi}{m}=k_P{ }^{1 / n}\right)$ plot of $\log \frac{x}{m} v s \log p$, the intercept is (where, $x, m, p$ and $k$ are mass of the gas, mass of adsorbent, pressure and constant which depend on the nature of the adsorbent, respectively)

• A

  $k$
• Correct answer
  B

  $\log k$
• C

  $e^k$
• D

  $\ln \frac{1}{k}$

Solution

For Freundlich adsorption isotherm equation $$ \frac{x}{m}=k_p^{\frac{1}{n}} $$ or $$ \log \frac{x}{m}=\log k+\frac{1}{n} \log p $$ A plot of $\log \frac{x}{m}$ versus $\log p$ is linear with slope $=\frac{1}{n}$ and intercept $=\log k$.

Hence, the correct answer is option: 'B'.