Q10 / 60 · JEE Advanced 2012 (Paper 2) · Chemistry
In the following reaction sequence, the compound $\mathrm{J}$ is an intermediate.
$\mathbf{J}\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{2}\right)$ gives effervescence on treatment with $\mathrm{NaHCO}_{3}$ and a positive Baeyer's test. Question: The compound $\mathbf{K}$ is
$\mathbf{J}\left(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{2}\right)$ gives effervescence on treatment with $\mathrm{NaHCO}_{3}$ and a positive Baeyer's test. Question: The compound $\mathbf{K}$ is
- A
- Correct answerB
- C
- D
Hence, the correct answer is option: 'B'.