In the following reaction, Ethyl alcohol $+\mathrm{H}^{+} \quad \frac{413 \mathrm{~K}}{\longrightarrow}$ $\begin{array}{ll}\text { (in excess) } & \text { (from } \mathrm{H}_{2} \mathrm{SO}_{4} \text { ) }\end{array}$ product, the product is

• A

  ethene
• B

  ethyl hydrogen sulphate
• Correct answer
  C

  diethyl ether
• D

  acetylene

Hence, the correct answer is option: 'C'.