Q128 / 150 · MHT CET 2025 (21 Apr Shift 2) · Physics

In the following combination of logic gates, the output $Y$ can be written in the terms of inputs A and B as Figure

  • A
    $(\mathrm{A} \cdot \overline{\mathrm{B}})+(\overline{\mathrm{A}} \cdot \mathrm{B})$
  • B
    $(\mathrm{A} \cdot \mathrm{B})+(\overline{\mathrm{A}} \cdot \mathrm{B})$
  • Correct answer
    C
    $(\overline{\mathrm{A} \cdot \mathrm{B}})+(\overline{\mathrm{A}} \cdot \mathrm{B})$
  • D
    $(\overline{\mathrm{A} \cdot \mathrm{B}})+(\mathrm{A} \cdot \overline{\mathrm{B}})$

Solution

Circuit output analysis: The circuit contains two AND gates, one OR gate, and two NOT gates arranged in parallel branches feeding the final OR gate.

The top branch processes inputs through an AND gate followed by a NOT gate, producing the term $\overline{A \cdot B}$.

The bottom branch processes input $B$ through a NOT gate before combining with $A$ in an AND gate, yielding $A \cdot \overline{B}$.

The final output $Y$ is the OR combination of these branch outputs: $Y = (\overline{A \cdot B}) + (A \cdot \overline{B})$.

This expression corresponds to option D.

Final answer: $\boxed{\text{D}}$

Hence, the correct answer is option: 'C'.

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