Q9 / 90 · KVPY 2012 (SB/SX) · Chemistry
In the DNA of E. Coli the mole ratio of adenine to cytosine is $0.7$. If the number of moles of adenine in the DNA is 350000 , the number of moles of guanine is equal to -
- A350000
- Correct answerB500000
- C225000
- D700000
Solution
$\begin{array}{l}
\frac{A}{C}=0.7 \\
\frac{35 \times 10^{4}}{C}=0.7 \\
C=\frac{35 \times 10^{4}}{0.7}=5 \times 10^{5}
\end{array}$
Moles of cytosine $=$ moles of guanine
Hence, the correct answer is option: 'B'.