In the circuit shown, initially there is no charge on capacitors and keys ${\mathrm{S}}_1$ and ${\mathrm{S}}_2$ are open. The values of the capacitors are ${\mathrm{C}}_1=10\mathrm{\mu }\mathrm{F},{\mathrm{C}}_2=30\mathrm{\mu }\mathrm{F}$ and ${\mathrm{C}}_3={\mathrm{C}}_4=80\mathrm{\mu }\mathrm{F}.$

Which of the statement(s) is/are correct?

• A

  If key ${\mathrm{S}}_1$ is kept closed for long time such that capacitors are fully charged, the voltage difference between points $\mathrm{P}$ and $\mathrm{Q}$ will be $10\mathrm{ }\mathrm{V}.$
• B

  The keys ${\mathrm{S}}_1$ is kept closed for long time such that capacitors are fully charged. Now key ${\mathrm{S}}_2$ is closed, at this time, the instantaneous current across $30\mathrm{ }\mathrm{\Omega }$ resistor (between points $\mathrm{P}$ and $\mathrm{Q}$ ) will be $0.2\mathrm{ }\mathrm{A}$ (round off to $1^{\mathrm{s}\mathrm{t}}$ decimal place).
• Correct answer
  C

  At time $\mathrm{t}=0,$ the key ${\mathrm{S}}_1$ is closed, the instantaneous current in the closed circuit will be $25\mathrm{ }\mathrm{m}\mathrm{A}.$
• Correct answer
  D

  If key ${\mathrm{S}}_1$ is kept closed for long time such that capacitors are fully charged, the voltage across the capacitors ${\mathrm{C}}_1$ will be $4\mathrm{V}.$

Hence, the correct answer is options: 'C', 'D'.