Q39 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

In the circuit shown in figure, the base current $I_{B}$ is $10 μA$ and the collector current is $5.2 mA$ . The voltage ( $V_{BE}$ ) across the base and emitter is

A
$0.1 V$
Correct answer
B
$0.5 V$
C
$0.25 V$
D
$0.7 V$

Solution

$V_{B E} = V_{C C} - I_{B} R_{B}$

$V_{B E} = 5.5 - (10 \times 10^{- 6}) \times (5 \times 10^{5}) = 0.5 V$

Hence, the correct answer is option: 'B'.

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