In the circuit shown assume the diode to be ideal. When $V_{i}$ increases from $2 \mathrm{V}$ to $6 \mathrm{V},$ the change in the current is (in mA)

• A

  zero
• Correct answer
  B

  20
• C

  $80 / 3$
• D

  40

Solution

$I_{\text {intitial }}=0$, $I_{\text {final }}=\frac{3}{150}=0.02 \mathrm{A}$ So, change in $I=0.02 \mathrm{A}=20 \mathrm{mA}$

Hence, the correct answer is option: 'B'.