Q11 / 150 · MHT CET 2016 · Chemistry

In the cell represented $P b_{(s)} |P b_{(1 M)}^{2 +}| |A g_{(1 M)}^{+}| A g_{(s)}$ , the reducing agent is

Correct answer
A
$P b$
B
$P b^{2 +}$
C
$A g$
D
$A g^{+}$

Solution

P b_{(s)} |P b_{(1 m)}^{2 +}| |A g_{(1 m)}^{+}| A g_{(s)}

The element losing

e^{-}

is called the reducing agent.

P b ⟶ P b^{2 +} + 2 e^{-}

Hence, the correct answer is option: 'A'.

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