Q6 / 170 · Manipal (MET) 2020 · Chemistry

In the Cannizzaro reaction given below $2 \mathrm{C}_6 \mathrm{H}_5 \mathrm{CHO} \xrightarrow{\mathrm{OH}^{-}} \mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{OH}+\mathrm{C}_6 \mathrm{H}_5 \mathrm{COO}^{-}$ The slowest step is

  • A
    The attack of $\mathrm{OH}^{-}$at the carbonyl group
  • Correct answer
    B
    The transfer of hydride ion to the carbonyl aroun
  • C
    The abstraction of proton from the carboxylic acid
  • D
    The deprotonation of benzyl alcohol

Solution

Figure
$\mathrm{H}^{-}$ is obtained by fission of $\mathrm{C}-\mathrm{H}$ bond of $(\mathrm{B})$. It is transferred to (II). This is the slowest step.

Hence, the correct answer is option: 'B'.

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