In the above circuit, $C=\frac{\sqrt{3}}{2}\mu F,R_2=20\mathrm{ \Omega },L=\frac{\sqrt{3}}{10}H$ and $R_1=10\mathrm{ \Omega }.$ Current in $L\text{-}{R}_1$ path is $I_1$ and in $C-R_2$ path it is $I_2.$ The voltage of $$AC source is given by, $V=200\sqrt{2}\sin \left(100t\right)$ volts. The phase difference between $I_1$ and $I_2$ is:

• A

  ${60}^o$
• B

  $0^o$
• C

  ${30}^o$
• Correct answer
  D

  ${150}^o$

Hence, the correct answer is option: 'D'.