Q177 / 180 · KCET 2023 · Physics
In series $L C R$ circuit at resonance, the phase difference between voltage and current is
- Correct answerAZero
- B$\pi$
- C$\frac{\pi}{4}$
- D$\frac{\pi}{2}$
Solution
In $L-C-R$ series resonance circuit,
$X_L=X_C$
$\therefore \tan \phi=\frac{X_L-X_C}{R}=\frac{0}{R}=0$
$\Rightarrow \quad \phi=0^{\circ}$
Hence, the correct answer is option: 'A'.