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Q144 / 180 · AIIMS 2001 · Physics

Q50 / 51 · AIIMS 2001 · Physics · Dual Nature of Matter · Photoelectric Effect

In Planck's oscillator energy is given as $$ E=\frac{h v}{\exp \left(\frac{h v}{K t}-1\right)} $$ If $K=0$, then energy would be

  • A
    $h \mathrm{v}$
  • Correct answer
    B
    0
  • C
    $\mathrm{Kt}$
  • D
    $\infty$.

Hence, the correct answer is option: 'B'.

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