Q56 / 180 · KCET 2022 · Chemistry

In oxygen and carbon molecule the bonding is

  • A
    $\mathrm{O}_2: 2 \sigma, 0 \pi ; \mathrm{C}_2: 0 \sigma, 2 \pi$
  • Correct answer
    B
    $\mathrm{O}_2: 1 \sigma, 1 \pi ; \mathrm{C}_2: 0 \sigma, 2 \pi$
  • C
    $\mathrm{O}_2: 0 \sigma, 2 \pi ; \mathrm{C}_2: 2 \sigma, 0 \pi$
  • D
    $\mathrm{O}_2: 1 \sigma, 1 \pi ; \mathrm{C}_2: 1 \sigma, 1 \pi$

Solution

The bond order of $\mathrm{C}_2$ consists of both pi bond because of the presence of the four electrons in two pi molecular orbitals. Whereas in most of the other molecules a double bond is made up of a sigma bond and a pi bond. Thus, option (b) is correct.

Hence, the correct answer is option: 'B'.

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