In keto-enol tautomerism of dicarbonyl compounds; the enol-form is preferred in contrast to the keto-form, this is due to

• A

  presence of carbonyl group on each side of $-\mathrm{CH}_{2}-$ group
• Correct answer
  B

  resonance stabilisation of enol form
• C

  presence of methylene group
• D

  rapid chemical exchange

Solution

Resonance stabilisation of enol form is

Hence, the correct answer is option: 'B'.