Q104 / 150 · MHT CET 2024 (16 May Shift 1) · Physics
In $\mathrm{M}_{\mathrm{O}}$ is the mass of an oxygen isotope ${ }_8 \mathrm{O}^{17}$ and $M_p$ and $M_N$ are the mass of proton and mass of neutron respectively, then the nucleus binding energy of the isotope is
- A$\quad \mathrm{M}_{\mathrm{o}} \mathrm{C}^2$
- B$\quad\left(\mathrm{M}_{\mathrm{O}}-8 \mathrm{M}_{\mathrm{p}}\right) \mathrm{C}^2$
- C$\left(\mathrm{M}_{\mathrm{O}}-17 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2$
- Correct answerD$\left(\mathrm{M}_{\mathrm{o}}-8 \mathrm{M}_{\mathrm{p}}-9 \mathrm{M}_{\mathrm{N}}\right) \mathrm{C}^2$
Solution
Number of protons $=8$
Number of neutrons $=17-8=9$
Binding energy,
$\begin{aligned}
B E & =\left(M_{\text {nucleus }}-M_{\text {nucleons }}\right) C^2 \\
& =\left(M_0-8 M_p-9 M_N\right) C^2
\end{aligned}$
Hence, the correct answer is option: 'D'.