In how many of the following compounds of sulphur, the oxidation state of sulphur atom is $+6 ?$

${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8, {\mathrm{H}}_2{\mathrm{SO}}_5, {\mathrm{H}}_2{\mathrm{SO}}_3, {\mathrm{H}}_2{\mathrm{SO}}_4, {\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_7, {\mathrm{SO}}_2{\mathrm{Cl}}_2, {\mathrm{SOCl}}_2$

The following compounds of sulphur, the oxidation state of sulphur atom is $+6$ as: ${\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_8, {\mathrm{H}}_2{\mathrm{SO}}_5, {\mathrm{H}}_2{\mathrm{SO}}_4, {\mathrm{H}}_2{\mathrm{S}}_2{\mathrm{O}}_7, {\mathrm{SO}}_2{\mathrm{Cl}}_2$.

In cass of ${\mathrm{H}}_2{\mathrm{SO}}_5, \mathrm{S}$bonded to four oxygen atom and shows $+6$ Oxidation state. Similarly, all above $\mathrm{S}$ shows $+6$ oxidation state.