In common emitter configuration of a transistor, current gain is more than 1 because $\left[\mathrm{I}_{\mathrm{b}}, \mathrm{I}_{\mathrm{e}}\right.$ and $\mathrm{I}_{\mathrm{c}}$ are base, emitter and collector currents respectively

• A

  $\mathrm{I}_{\mathrm{c}} < \mathrm{I}_{\mathrm{b}}$
• B

  $\mathrm{I}_{\mathrm{b}} < \mathrm{I}_{\mathrm{e}}$
• C

  $\mathrm{I}_{\mathrm{c}} < \mathrm{I}_{\mathrm{e}}$
• Correct answer
  D

  $\mathrm{I}_{\mathrm{c}}>\mathrm{I}_{\mathrm{b}}$

Hence, the correct answer is option: 'D'.