In Bohr's theory of Hydrogen atom, the electron jumps from higher orbit n to lower orbit p. The wavelength will be maximum for the transition

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Correct answer: (A) n=5 to p=4. According to Bohr's theory the wavelength of radiation emitted is given by 1/(λ)=R1/(ni^2)-1/(nf^2) For n_i=5 and n_f=4 , the wavelength emitted will be longest as energy difference ∆E=E_5-E_4 is very small.

In Bohr's theory of Hydrogen atom, the electron jumps from higher orbit $n$ to lower orbit $p$ . The wavelength will be maximum for the transition

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