Q16 / 160 · WBJEE 2015 · Chemistry

In aqueous alkaline solution, two electrons reduction of $\mathrm{HO}_{2}^{-}$ gives

  • Correct answer
    A
    $\mathrm{HO}^{-}$
  • B
    $\mathrm{H}_{2} \mathrm{O}$
  • C
    $\mathrm{O}_{2}$
  • D
    $O_{2}^{-}$

Solution

In aqueous alkaline solution, two electron reduction of $\mathrm{HO}_{2}^{-}$ gives OH The reaction is as follows: $\begin{array}{l} \mathrm{H}_{2} \mathrm{O}_{2} \rightleftharpoons \mathrm{H}^{+}+\mathrm{HO}_{2}^{-} \\ \mathrm{HO}_{2}^{-}+\mathrm{H}_{2} \mathrm{O}+2 e^{-} \rightleftharpoons 3 \mathrm{OH} \end{array}$

Hence, the correct answer is option: 'A'.

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