Q66 / 90 · JEE Main 2009 · Physics
In an optics experiment, with the position of the object fixed, a student varies the position of a convex lens and for each position, the screen is adjusted to get a clear image of the object. A graph between the object distance $u$ and the image distance $v$, from the lens, is plotted using the same scale for the two axes. A straight line passing through the origin and making an angle of $45^{\circ}$ with the x-axis meets the experimental curve at $P$. The coordinates of $P$ will be
- Correct answerA$(2 f, 2 f)$
- B$\left(\frac{f}{2}, \frac{f}{2}\right)$
- C$(f, f)$
- D$(4 f, 4 f)$
Solution
It is possible when object kept at centre of curvature.
$$
\begin{aligned}
& u=v \\
& u=2 f, v=2 f .
\end{aligned}
$$


Hence, the correct answer is option: 'A'.