In an experiment on the photoelectric effect, the de Broglie wavelength of the emitted electron is $\lambda_B$. The energy of the photon incident on the metal is five times the work function. If $h$ is Planck's constant and $m_e$ is the electron mass, then what is the work function?

• A

  $\frac{h^2}{12 m_e \lambda_B^2}$
• B

  $\frac{h^2}{4 m_e \lambda_B^2}$
• Correct answer
  C

  $\frac{h^2}{8 m_e \lambda_B^2}$
• D

  $\frac{h^2}{10 m_c \lambda_B^2}$

Hence, the correct answer is option: 'C'.