Q182 / 200 · TS EAMCET 2001 · Physics

In an experiment of simple pendulum, the errors in the measurement of length of the pendulum $(L)$ and time period $(T)$ are $3 \%$ and $2 \%$, respectively. The maximum percentage error in the value of $\frac{L}{T^2}$ is

  • A
    $\mathbf{5} \%$
  • Correct answer
    B
    $7 \%$
  • C
    $8 \%$
  • D
    $1 \%$

Solution

Maximum percentage in the value of $\frac{L}{T^3}$ $\begin{aligned} & =\frac{\Delta L}{L} \times 100 \%+2 \frac{\Delta T}{T} \times 100 \% \\ & =3+2 \times 2=7 \%\end{aligned}$

Hence, the correct answer is option: 'B'.

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