Q140 / 180 · COMEDK 2013 · Physics
In an $L-C-R$ circuit, the potential difference between the terminals of the inductance is $60 \mathrm{~V}$, between the terminals of the capacitor is $30 \mathrm{~V}$ and that between the terminals of resistance is $40 \mathrm{~V}$. The supply voltage will be equal to
- A$130 \mathrm{~V}$
- B$10 \mathrm{~V}$
- Correct answerC$50 \mathrm{~V}$
- D$70 \mathrm{~V}$
Solution
Given, $V_{R}=40 \mathrm{~V}, V_{L}=60 \mathrm{~V}, V_{C}=30 \mathrm{~V}$
For an $L-C-R$ circuit, the supply voltage
$$
\begin{aligned}
V &=\sqrt{V_{R}^{2}+\left(V_{L}-V_{C}\right)^{2}} \\
&=\sqrt{40^{2}+(60-30)^{2}} \\
&=\sqrt{40^{2}+30^{2}} \\
&=\sqrt{1600+900}=\sqrt{2500}=50 \mathrm{~V}
\end{aligned}
$$
Hence, the correct answer is option: 'C'.