In an aqueous solution, glucose exists in cyclic and open-chain forms, in equilibrium, as shown below. Glucose solution does not give positive Schiff test.


The correct statement is:

• A

  $\alpha-\mathrm{D}(+)$-glucose and $\beta-\mathrm{D}(+)$-glucose are enantiomers.
• Correct answer
  B

  $\alpha-\mathrm{D}(+)$-glucose and $\beta-\mathrm{D}(+)$-glucose are anomers.
• C

  In solution, the open-chain form predominates over the cyclic forms.
• D

  Glucose reacts with sodium bisulphite to form an addition product.

Hence, the correct answer is option: 'B'.