$\mathrm{AlCl}_3$ in an acidified aqueous solution forms an $\mathrm{Al}^{3+}$ complex. In this complex ion, the hybridization of Al is

• A

  $\mathrm{dsp}^2$
• B

  $\mathrm{sp}^3 \mathrm{~d}$
• C

  $\mathrm{sp}^2$
• Correct answer
  D

  $\mathrm{sp}^3 \mathrm{~d}^2$

Hence, the correct answer is option: 'D'.