In an a.c. circuit the voltage applied is $\mathrm{E}=\mathrm{E}_0 \sin \omega \mathrm{t}$. The resulting current in the circuit is $\mathrm{I}=\mathrm{I}_0 \sin \left(\omega \mathrm{t}-\frac{\pi}{2}\right)$. The power consumption in the circuit is given by

• A

  $\mathrm{P}=\frac{\mathrm{E}_0 \mathrm{I}_0}{\sqrt{2}}$
• Correct answer
  B

  $\mathrm{P}=$ zero
• C

  $\mathrm{P}=\frac{\mathrm{E}_0 \mathrm{I}_0}{2}$
• D

  $\mathrm{P} \sqrt{2} \mathrm{E}_0 \mathrm{I}_0$

Hence, the correct answer is option: 'B'.