In an A.C. circuit, the instantaneous e.m.f. and current are given by, E=100sin30t,I=20sin30t-(π)/4. In one cycle of A.C., the average power consumed…

Question

In an A.C. circuit, the instantaneous e.m.f. and current are given by, E=100sin30t,I=20sin30t-(π)/4. In one cycle of A.C., the average power consumed by the circuit (in watt) and the watt-less current (in ampere) are, respectively:

MARKS Content Team · Accepted Answer

Correct answer: (C) 1000/(√2), 10. Instantaneous emf and current is given by, E=100sin30t, I=20sin30t-(π)/4. Phase difference between emf and current is ϕ=30t-30t-(π)/4=(π)/4 Average power is given by, P_av=E_rmsI_rmscosϕ =100/(√2)×20/(√2)×1/(√2)=1000/(√2) Watt-less current is given by, I_WL=I_rmssinϕ=I_o√2sin45°⇒I_WL=20√2.1√2=10 A.

In an $A.C.$ circuit, the instantaneous e.m.f. and current are given by, $E = 100 \sin 30 t$ $, I = 20 \sin (30 t - \frac{π}{4})$ . In one cycle of $A.C.$ , the average power consumed by the circuit (in watt) and the watt-less current (in ampere) are, respectively:

Solution

Relevant Questions

In an A.C. circuit, the instantaneous e.m.f. and current are given by, E=100sin30t,I=20sin30t-π4. In one cycle of A.C., the average power consumed by the circuit (in watt) and the watt-less current (in ampere) are, respectively:

Solution

Relevant Questions

In an $A.C.$ circuit, the instantaneous e.m.f. and current are given by, $E = 100 \sin 30 t$ $, I = 20 \sin (30 t - \frac{π}{4})$ . In one cycle of $A.C.$ , the average power consumed by the circuit (in watt) and the watt-less current (in ampere) are, respectively: