Q143 / 150 · MHT CET 2022 (07 Aug Shift 2) · Physics

In an a. c. circuit the instantaneous current and e.m.f. are represented as $i=i_o \sin \left(\omega t-\frac{\pi}{6}\right)$ and $E=E_o \sin \left(\omega t+\frac{\pi}{3}\right)$ respectively. The voltage leads the current by

  • Correct answer
    A
    $\frac{\pi}{2}$
  • B
    $\frac{\pi}{4}$
  • C
    $\frac{\pi}{3}$
  • D
    $\frac{\pi}{6}$

Solution

The phase of the current $=-\frac{\pi}{6}$ The phase of voltage $=+\frac{\pi}{3}$ Hence the voltage leads current by phase angle $\phi=\left(\frac{\pi}{6}\right)-\left(-\frac{\pi}{3}\right)=\frac{\pi}{2}$

Hence, the correct answer is option: 'A'.

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