In a Young's double slit experiment, an angular width of the fringe is 0.35° on a screen placed at 2 m away for particular wavelength of 450 nm. The…

Question

In a Young's double slit experiment, an angular width of the fringe is 0.35° on a screen placed at 2 m away for particular wavelength of 450 nm. The angular width of the fringe, when whole system is immersed in a medium of refractive index 7/5, is 1/(α). The value of α is _____ .

MARKS Content Team · Accepted Answer

Correct answer: 4. Angular fringe width is given by θ=(λ)/D, where, D is the distance between the source and the screen and λ is the wavelength of the light. We have, θ_1θ_2=λ_1λ_2 Then, θ_2=0.35^(∘)450 nm×(450 nm)/75=0.25^(∘)=1/4 ∵λ_2=λ_1μ Thus, value of α=4.

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In a Young's double slit experiment, an angular width of the fringe is 0.35° on a screen placed at 2 m away for particular wavelength of 450 nm. The angular width of the fringe, when whole system is immersed in a medium of refractive index 75, is 1α. The value of α is _____ .

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