Q94 / 180 · NEET 2026 (Cancelled) · Chemistry

In a test tube containing a salt, a few drops of dilute $\text{H}_2\text{SO}_4$ was added, which gave colourless vapours having the smell of vinegar. The vapours turned the blue litmus paper red. Identify the correct anion from the following :

  • A
    Sulphide, $\text{S}^{2-}$
  • B
    Sulphate, $\text{SO}_4^{2-}$
  • Correct answer
    C
    Acetate, $\text{CH}_3\text{COO}^{-}$
  • D
    Carbonate, $\text{CO}_3^{2-}$

Solution

When a salt containing the acetate anion ($\text{CH}_3\text{COO}^{-}$) is treated with dilute $\text{H}_2\text{SO}_4$, acetic acid ($\text{CH}_3\text{COOH}$) is formed.

$2\text{CH}_3\text{COO}^{-} + \text{H}_2\text{SO}_4 \rightarrow 2\text{CH}_3\text{COOH} + \text{SO}_4^{2-}$

Acetic acid vapours are colourless and have a characteristic smell of vinegar. Being acidic in nature, these vapours turn blue litmus paper red.

Sulphide ($\text{S}^{2-}$) gives $\text{H}_2\text{S}$ gas which has a rotten egg smell.

Sulphate ($\text{SO}_4^{2-}$) does not react with dilute $\text{H}_2\text{SO}_4$.

Carbonate ($\text{CO}_3^{2-}$) gives $\text{CO}_2$ gas which is odourless.

Answer: Acetate, $\text{CH}_3\text{COO}^{-}$

Hence, the correct answer is option: 'C'.

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